The maximum energy of the electrons released in photocell is independent of -

Options

A. Frequency of incident light.
B. Intensity of incident light.
C. Naure of cathode surface.
D. None of these.

Explanation

To solve the question regarding the maximum energy of electrons released in a photocell, we can follow these steps:

### Step 1: Understand the Photoelectric Effect
The photoelectric effect describes the phenomenon where electrons are emitted from a material (usually a metal) when it is exposed to light of sufficient frequency. The energy of the emitted electrons depends on the frequency of the incident light.

### Step 2: Use the Photoelectric Equation
The maximum kinetic energy (K.E.) of the emitted electrons can be expressed using the equation:
\[ K.E. = h\nu - \phi \]
where:
- \( K.E. \) is the maximum kinetic energy of the emitted electrons,
- \( h \) is Planck's constant,
- \( \nu \) is the frequency of the incident light,
- \( \phi \) is the work function of the material (the minimum energy needed to remove an electron from the surface).

### Step 3: Analyze the Variables
From the equation, we can see that:
- The maximum kinetic energy \( K.E. \) depends on the frequency \( \nu \) of the incident light and the work function \( \phi \) of the material.
- The work function \( \phi \) is a property of the cathode material used in the photocell.

### Step 4: Identify What K.E. Does Not Depend On
The intensity of the light affects the number of electrons emitted but does not affect the maximum kinetic energy of the emitted electrons. Therefore, the maximum energy of the electrons released is independent of the intensity of the incident light.

### Step 5: Conclusion
Based on our analysis, we conclude that the maximum energy of the electrons released in a photocell is independent of the intensity of the incident light.

### Final Answer
The correct option is **B: Intensity of the incident light**.

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