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A certain metallic surface is illuminated with monochromatic light of wavelength `lambda`. The stopping potential for photoelectric current for this light is `3V_(@)`. If the same surface is illuminated with light of wavelength `2lambda`, the stopping potential is `V_(0)`. The threshold wavelength for this surface for photoelectric effiect is

A

`6 lambda`

B

`4 lambda//3`

C

`4lambda`

D

`8lambda`

Text Solution

Verified by Experts

The correct Answer is:
C

`(e(6V_(0)))/(e(2V_(0))) = ((hc)/(lambda) - phi)/((hc)/(2lambda) - phi) rArr lambda_(0) = 4lambda`
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