The de Broglie waves are associated with moving particles. These particle may be

Options

A. electrons
B. `He^(+), Li^(2+)` ions
C. Cricket ball
D. All of the above

Explanation

**Step-by-Step Solution:**

1. **Understanding de Broglie Waves**: The de Broglie hypothesis states that every moving particle or object has an associated wave. This wave is known as the de Broglie wave.

2. **Formula for de Broglie Wavelength**: The de Broglie wavelength (λ) can be calculated using the formula:
\[ \lambda = \frac{h}{mv} \]
where \(h\) is Planck's constant, \(m\) is the mass of the particle, and \(v\) is its velocity.

3. **Identifying the Criteria for de Broglie Waves**: For a particle to have a de Broglie wavelength, it must possess both mass and velocity. This means that any object that has these two properties can be associated with de Broglie waves.

4. **Analyzing the Options**:
- **Option A (Electron)**: An electron has mass and can move, hence it has a de Broglie wavelength.
- **Option B (Helium and Lithium Ions)**: Both helium and lithium ions have mass and can move, thus they also possess de Broglie wavelengths.
- **Option C (Cricket Ball)**: A cricket ball has mass and can be thrown or hit, giving it velocity, so it too has a de Broglie wavelength.

5. **Conclusion**: Since all the given options (A, B, and C) represent particles that have mass and velocity, we can conclude that all options are correct.

**Final Answer**: All options (A, B, and C) are correct as they all can possess de Broglie waves.

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