If 13.6 eV energy is required to lionize...

If 13.6 eV energy is required to lionize the hydrogen atm, then energy required to remove an electron from n = 2 is :

A

`10.2 eV`

B

`0 eV`

C

`3.4 eV`

D

`6.8 eV`

Text Solution

Verified by Experts

The correct Answer is:

C

`E = (13.6 eV)/(2^(2)) = 3.4 eV`

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