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Energy of 24.6 eV is required to remove ...

Energy of 24.6 eV is required to remove one of the electron from a neutral helium atom. The energy (in eV) required to remove both electrons from a neutral helium atom is

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The correct Answer is:
D

`E = 24.6 + (13.6(2)^(2))/(1^(2)) = 79.0 eV`
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ALLEN-SIMPLE HARMONIC MOTION-Exercise-01
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