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The K(alpha) X-ray emission line of tung...

The `K_(alpha)` X-ray emission line of tungsten occurs at `lambda = 0.02 nm`. The energy difference between `K and L` level in this atom is about

A

`0.51 MeV`

B

`1.2 MeV`

C

`59 keV`

D

`13.6 eV`

Text Solution

Verified by Experts

The correct Answer is:
C
`E = (hc)/(lambda) = (1242eV - nm)/(0.021 nm) = 59 keV`
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