For the decay of nucleus, the possible reason which is not true

Options

A. Neutron proton ratio too high
B. Neutron proton ratio too low
C. Size of nucleus ratio too low
D. Binding energy of nucleus is more than that of its products

Answer

To solve the question regarding the possible reasons for the decay of a nucleus and identifying which statement is not true, we can follow these steps:

### Step 1: Understand the Concept of Nuclear Stability
The stability of a nucleus is primarily determined by the ratio of neutrons to protons. An ideal ratio for stability is approximately 1:1. If this ratio is too low (too few neutrons) or too high (too many neutrons), the nucleus becomes unstable and is likely to undergo decay.

**Hint:** Consider how the neutron-to-proton ratio affects nuclear stability.

### Step 2: Analyze the Statements
We need to evaluate the given statements regarding nuclear decay and identify which one is not true. The statements typically involve:
- Neutron-to-proton ratios
- Size of the nucleus
- Binding energy

**Hint:** Look for statements that contradict the established principles of nuclear physics.

### Step 3: Evaluate Each Statement
1. **Neutron-to-proton ratio too low or too high:** This statement is true. An unstable nucleus will decay if the neutron-to-proton ratio is not optimal.

2. **Size of the nucleus:** A statement about the size of the nucleus affecting stability is also true. If the nucleons are too close or too far apart, it can lead to instability.

3. **Binding energy of the nucleus:** The binding energy represents how tightly the nucleons are held together. A higher binding energy indicates a more stable nucleus. Thus, if the binding energy is more than its product (which could imply a comparison to the total mass-energy), this would indicate that the nucleus is stable, not unstable.

**Hint:** Consider how binding energy relates to the stability of the nucleus.

### Step 4: Identify the Not True Statement
From the evaluation, the statement regarding binding energy being more than its product is not true in the context of nuclear decay. A higher binding energy means greater stability, not instability.

**Conclusion:** The statement that is not true regarding the decay of a nucleus is related to the binding energy.

**Final Answer:** The not true option is related to the binding energy of the nucleus being more than its product.