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The mass of proton is 1.0073 u and that ...

The mass of proton is 1.0073 u and that of neutron is 1.0087 u (u = atomic mass unit). The binding energy of `._2^4He` is (Given : helium nucleus mass `approx` 4.0015 u)

A

`0.0305 J`

B

`0.0305 erg`

C

`28.4 MeV`

D

`0.061 u`

Text Solution

Verified by Experts

The correct Answer is:
C
`._(2)^(4)He -= 2n + p`
`BE = [2(1.0073 + 1.0087) - 4 .0015]931.5MeV`
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