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In a mean life of a radioactive sample...

In a mean life of a radioactive sample

A

about `2//3` of substance disintefrates

B

about `2//3` of substanced disintegrates

C

about `90%` of the substance disintegrates

D

almost all the substance disintegrates

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The correct Answer is:
To solve the problem regarding the mean life of a radioactive sample, we can follow these steps: ### Step 1: Understand the decay formula The decay of a radioactive substance can be described by the equation: \[ n = n_0 e^{-\lambda t} \] where: - \( n \) is the number of undecayed nuclei at time \( t \), - \( n_0 \) is the initial number of nuclei, - \( \lambda \) is the decay constant, - \( e \) is the base of the natural logarithm. ### Step 2: Relate mean life to decay constant The mean life (or average lifetime) \( \tau \) of a radioactive sample is given by: \[ \tau = \frac{1}{\lambda} \] ### Step 3: Substitute mean life into the decay formula Using the mean life, we can express the decay formula in terms of \( \tau \): \[ n = n_0 e^{-\frac{t}{\tau}} \] ### Step 4: Determine the amount of substance remaining after one mean life After one mean life (\( t = \tau \)): \[ n = n_0 e^{-1} \] Since \( e^{-1} \) is approximately \( \frac{1}{e} \), we can say: \[ n \approx \frac{n_0}{e} \] ### Step 5: Calculate the amount of substance disintegrated The amount of substance that has disintegrated can be calculated as: \[ \text{Disintegrated} = n_0 - n \] Substituting the value of \( n \): \[ \text{Disintegrated} = n_0 - \frac{n_0}{e} = n_0 \left(1 - \frac{1}{e}\right) \] ### Step 6: Calculate the fraction of substance disintegrated The fraction of the substance that has disintegrated is: \[ \frac{\text{Disintegrated}}{n_0} = 1 - \frac{1}{e} \] Using the approximation \( e \approx 2.718 \), we find: \[ 1 - \frac{1}{e} \approx 1 - 0.3679 \approx 0.6321 \] This means approximately 63.21% of the substance has disintegrated. ### Step 7: Determine the fraction in terms of \( n_0 \) To express this as a fraction of \( n_0 \): \[ \text{Disintegrated} \approx 0.6321 n_0 \] This can be approximated as: \[ \text{Disintegrated} \approx \frac{2}{3} n_0 \] ### Conclusion Thus, approximately \( \frac{2}{3} \) of the substance has disintegrated after one mean life. ### Final Answer The correct option is B: about \( \frac{2}{3} \) of the substance has disintegrated. ---

To solve the problem regarding the mean life of a radioactive sample, we can follow these steps: ### Step 1: Understand the decay formula The decay of a radioactive substance can be described by the equation: \[ n = n_0 e^{-\lambda t} \] where: - \( n \) is the number of undecayed nuclei at time \( t \), - \( n_0 \) is the initial number of nuclei, ...
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