Home
Class 12
PHYSICS
A fission reaction is given by (92)^(236...

A fission reaction is given by `_(92)^(236) U rarr_(54)^(140) Xe + _(38)^(94)St + x + y` , where x and y are two particle Consider `_(92)^(236) U` to be at rest , the kinetic energies of the products are deneted by `k_(xe) K _(st) K _(x) (2MeV ) and `Ky(2MeV) repectively . Let the binding energy per nucleus of `_(92)^(236) U, _(54)^(140) Xe and _(38)^(94)St be 7.5 MeV , 8.4 MeV and 8.5 MeV, ` respectively Considering different conservation laws, the correct option (s) is (are)

A

`x = n, y = n, K_(Sr) = 129 MeV, K_(xe) = 86 MeV`

B

`x = p, y = e^(-), K_(Sr) = 129 MeV, K_(xe) = 86 MeV`

C

`x = p, y = n, K_(Sr) = 129 MeV, K_(xe) = 86 MeV`

D

`x = n, y = n, K_(Sr) = 86 MeV, K_(xe) = 129 MeV`

Text Solution

Verified by Experts

The correct Answer is:
A
`U rarr Xe+Sr+underset(2)(x)+underset(2)(y)`
`Q=4+K_(xe)+K_(sr)` …(i)
`-Q=E_(B)=236xx7.5-140xx8.5-94xx8.5`
`:. Q=219` …(ii)
`:. K_(xe)+K_(sr)=215 MeV`
Since, both x & y have same KE
`:.` both particles should have same mass & lighter body will have higher KE.
`:.` Ans. (A)
Promotional Banner

Topper's Solved these Questions

  • SIMPLE HARMONIC MOTION

    ALLEN|Exercise Comprehension #1|3 Videos

  • SIMPLE HARMONIC MOTION

    ALLEN|Exercise Comprehension #2|3 Videos

  • SIMPLE HARMONIC MOTION

    ALLEN|Exercise Exercise-05(B)|46 Videos

  • RACE

    ALLEN|Exercise Basic Maths (Wave Motion & Dopplers Effect) (Stationary waves & doppler effect, beats)|24 Videos

  • TEST PAPER

    ALLEN|Exercise PHYSICS|4 Videos

Similar Questions

Explore conceptually related problems

Binding energies of ._1H^2 , ._2He^4 , ._26Fe^56 and ._92U^235 nuclei are 2.22Mev, 28.4Mev, 492Mev and 1786MeV respectively which one of the following is more stable?

Consider the nuclear fission Ne^(20) rarr 2He + C^(12) .The binding energy per nucleon are 8.03 MeV, 7.07 MeV and 7.86 MeV respectively. identify the correct statement

A ._(92)^(238)U undergoes alpha decay. What is the resulting daughter nucleus?

Obtain the binding energy (in MeV) of a nitrogen nucleus (""_(7)^(14)N) , given m(""_(7)^(14)N) =14.00307" "u

In a fission reaction ._92^236 U rarr ^117 X + ^117Y + n + n , the binding energy per nucleon of X and Y is 8.5 MeV whereas of .^236 U is 7.6 MeV . The total energy liberated will be about.

In the nuclear reaction U_92^238 to Pb_82^206 + xHe_2^4 + y beta_(-1)^0 the value of x and y are respectively ………

In the disintegration series ._(92)^(238)U overset rarr (alpha) X overset rarr (beta^(-))._Z^(A)Y the values of Z and A , respectively, will be

Stationary nucleus ._(92)^(238)U decays by a emission generating a total kinetic energy T: ._(92)^(238)U rarr ._(90)^(234)Th +._2^4 alpha What is the kinetic energy of the alpha -particle?

At what displacement the kinetic is equal to the potential energy ? Hint : U = (1)/(2) kx^(2) , K = (1)/(2) (A^(2) - x^(2)) U = K