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Highly excited states for hydrogen like ...

Highly excited states for hydrogen like atom (alos called Ryburg states) with nucleus Charge Ze are defined by their principal qunatum number n, where `n lt lt 1`. Which of the following statement(s) is (are) true?

A

Releative change in the radii of two consecutive orbitals does not depend on `Z`

B

Relative change in the radii of two consecutive orbitals varies as `1//n`

C

Relative change in the energy of two consecutive orbitals varies as `1//n^(2)`

D

Relative change in the angular momenta of two consecutive orbitals varies as `1//n`

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To solve the question regarding the highly excited states (Rydberg states) for hydrogen-like atoms with nucleus charge \( Ze \), we need to analyze the given statements one by one. ### Step-by-Step Solution: 1. **Understanding the Rydberg Formula for Radius**: The radius of the nth orbit for a hydrogen-like atom is given by: \[ R_n = \frac{0.529 \, n^2}{Z} \] where \( n \) is the principal quantum number and \( Z \) is the atomic number. 2. **Analyzing the First Statement**: The first statement claims that the relative change in the radii of two consecutive orbitals does not depend on \( Z \). - For two consecutive orbits \( n \) and \( n+1 \): \[ R_{n+1} = \frac{0.529 \, (n+1)^2}{Z} \] The change in radius \( \Delta R \) is: \[ \Delta R = R_{n+1} - R_n = \frac{0.529 \, ((n+1)^2 - n^2)}{Z} \] The expression simplifies to: \[ \Delta R = \frac{0.529 \, (2n + 1)}{Z} \] - The relative change in radius is: \[ \frac{\Delta R}{R_n} = \frac{(2n + 1)}{n^2} \] - Since \( Z \) cancels out, the first statement is **true**. 3. **Analyzing the Second Statement**: The second statement claims that the relative change in radii of two consecutive orbitals varies as \( \frac{1}{n} \). - From the previous calculation, we found: \[ \frac{\Delta R}{R_n} = \frac{(2n + 1)}{n^2} \] - For \( n \) very small, we can approximate: \[ \frac{(2n + 1)}{n^2} \approx \frac{2}{n} \] - Thus, the second statement is also **true**. 4. **Analyzing the Third Statement**: The third statement discusses the relative change in energy of two consecutive orbitals. - The energy of the nth orbital is given by: \[ E_n = -\frac{13.6 Z^2}{n^2} \] - The change in energy \( \Delta E \) is: \[ \Delta E = E_{n+1} - E_n = -\frac{13.6 Z^2}{(n+1)^2} + \frac{13.6 Z^2}{n^2} \] - Simplifying gives: \[ \Delta E = 13.6 Z^2 \left( \frac{1}{n^2} - \frac{1}{(n+1)^2} \right) = 13.6 Z^2 \cdot \frac{2n + 1}{n^2(n+1)^2} \] - The relative change in energy is: \[ \frac{\Delta E}{E_n} = \frac{2n + 1}{(n + 1)^2} \] - As \( n \) becomes very small, this does not simplify to \( \frac{1}{n^2} \) but rather to \( \frac{2}{n} \). Thus, the third statement is **false**. 5. **Analyzing the Fourth Statement**: The fourth statement claims that the relative change in angular momentum of two consecutive orbitals varies as \( \frac{1}{n} \). - The angular momentum for the nth orbital is given by: \[ L_n = n \hbar \] - The change in angular momentum \( \Delta L \) is: \[ \Delta L = L_{n+1} - L_n = (n + 1)\hbar - n\hbar = \hbar \] - The relative change is: \[ \frac{\Delta L}{L_n} = \frac{\hbar}{n\hbar} = \frac{1}{n} \] - Thus, the fourth statement is **true**. ### Conclusion: The true statements are A, B, and D.

To solve the question regarding the highly excited states (Rydberg states) for hydrogen-like atoms with nucleus charge \( Ze \), we need to analyze the given statements one by one. ### Step-by-Step Solution: 1. **Understanding the Rydberg Formula for Radius**: The radius of the nth orbit for a hydrogen-like atom is given by: \[ R_n = \frac{0.529 \, n^2}{Z} ...
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