identify the non-feasible reaction.

Options

A. `CH_(3)-C-=CH+NH_(2)^(-)hArrCH_(3)-C-=overset(underset(_)(* *))(C)+NH_(3)`
B. `CH_(3)CH_(2)-OH+NaH hArrCH_(3)CH_(2)ON a+H_(2)`
C. `CH_(3)-OH+NaOHhArrCH_(3)ON a+H_(2)O`
D. `HC-=CH+NaOHhArrCH-=CN a+H_(2)O`

Answer

To identify the non-feasible reaction among the given options, we need to analyze each reaction based on the acidity of the reactants and the basicity of the reagents involved. Here’s a step-by-step breakdown of the solution:

### Step 1: Analyze the First Reaction
- **Reaction**: Acetylene (C2H2) reacting with NH2⁻.
- **Products**: Acetylide ion (C2H−) and NH3.
- **Analysis**: Acetylene is a weak acid that can donate a proton (H⁺). NH2⁻ is a strong base that can accept this proton. The formation of a stabilized acetylide ion indicates that this reaction is feasible.

### Step 2: Analyze the Second Reaction
- **Reaction**: Ethanol (C2H5OH) reacting with NaH.
- **Products**: Sodium ethoxide (C2H5ONa) and H2.
- **Analysis**: Sodium hydride (NaH) is a strong base that can deprotonate ethanol, leading to the formation of sodium ethoxide and hydrogen gas (H2). This reaction is feasible.

### Step 3: Analyze the Third Reaction
- **Reaction**: Methanol (CH3OH) reacting with NaOH.
- **Products**: Sodium methoxide (CH3ONa) and H2.
- **Analysis**: Similar to the second reaction, NaOH is a strong base that can deprotonate methanol, resulting in the formation of sodium methoxide and hydrogen gas. This reaction is also feasible.

### Step 4: Analyze the Fourth Reaction
- **Reaction**: Acetylene (C2H2) reacting with NaOH.
- **Products**: Sodium acetylide (C2H−) and H2O.
- **Analysis**: Acetylene is a weak acid, and NaOH is a strong base. However, in this case, the weak acid (acetylene) cannot effectively react with the strong base (NaOH) to form the sodium acetylide and water. Therefore, this reaction is not feasible.

### Conclusion
After analyzing all four reactions, we find that the fourth reaction is the non-feasible one. Thus, the answer to the question is:

**Final Answer**: Option 4 is not feasible.

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