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An oleum sample is labelled as 118%, Cal...

An oleum sample is labelled as 118%, Calculate
Mass of `H_(2)SO_(4)` in 100 gm oleum sample

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The correct Answer is:
(i) 20gm; (ii) 35.4 gm; (iii) `H_(2)SO_(4) = 35.4 gm, H_(2)O = 34.6 gm`
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Calculate the molar mass of H_2SO_4

Similar to % labelling of oleum ,a mixture of H_(3)PO_(3) and P_(4)O_(6) is labelled as (100 +x)% where x is maximum mass of water which can reacts with P_(4)O_(6) present in 100 gm mixture of H_(3)PO_(3) and P_(4)O_(6) P_(4)O_(6) + H_(2)O rarr H_(3)PO_(3) If such a mixture is labelled as 127 % , then mass of free P_(4)O_(6) in given 100 g mixture is :

Find the mass of Free SO_(3) present in 100gm, 109% oleum sample

Oleum is mixture of H_(2)SO_(4) and SO_(3) i.e. H_(2)S_(2)O_(7) which is obtained by passing SO_(3) is solution of H_(2)SO_(4) . In order to dissolve SO_(3) in oleum, dilution of oleum is done by water in which oleum is converted into pure H_(2)SO as shown below: H_(2)SO_(4)+SO_(3)+H_(2)Oto2H_(2)SO_(4) (pure) When 100 gm oleum is diluted with water then total mass of diluted oleum is known as percentage labelling in oleum. For example: 109% H_(2)SO_(4) labelling of oleum sample means that 109 gm pure H_(2)SO_(4) is obtained on diluting 100 gm oleum with 9 gm H_(2)O which dissolves al free SO_(3) in oleum. If the number of moles of free SO_(3), H_(2)SO_(4) , and H_(2)O be x, y and z respectively in 118% H_(2)SO_(4) labelled oleum, the value of (x+y+z) is

If all hydrogen atoms are present in its isotopic form of deuterium (._1H^(2)) in an oleum sample. Calculate percentage by mass of sulphur in 118 % of one such oleum sample (SO_(3)+D_(2)SO_(4) ).

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25 gm of an oleum sample contains 15 gm H_(2)SO_(4) . What is % labellling of this oleum sample-

What is the maximum mass of H_(2)SO_(4) that can be obtained from a 100 gm oleum sample labelled as 110%

The percentage labelling (mixture of H_(2)SO_(4) and SO_(3)) refers to the total mass of pure H_(2)SO_(4) . The total amount of H_(2)SO_(4) found after adding calculated amount of water to 100 g oleum is the percentage labelling of oleum. Higher the percentage lebeling of oleum higher is the amount of free SO_(3) in the oleum sample. What is the amount of free SO_(3) in an oleum sample labelled as '118%'.

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ALLEN- CONCENTRATION TERMS-Exercise S - I
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