The weight of `2.01xx10^(22)` molecules of `CO` is-

Options

A. 0.924 g
B. 0.72 g
C. 1.2 g
D. 3 g

Explanation

To find the weight of \(2.01 \times 10^{22}\) molecules of carbon monoxide (CO), we can follow these steps:

### Step 1: Determine the number of moles from the number of molecules.
We know that one mole of any substance contains \(6.02 \times 10^{23}\) molecules (Avogadro's number). To find the number of moles (\(n\)) from the given number of molecules, we use the formula:

\[ n = \frac{\text{Number of molecules}}{6.02 \times 10^{23}} \]

Substituting the given number of molecules:

\[ n = \frac{2.01 \times 10^{22}}{6.02 \times 10^{23}} \]

### Step 2: Calculate the number of moles.
Now we perform the calculation:

\[ n = \frac{2.01}{6.02} \times 10^{-1} = 0.0334 \text{ moles} \]

### Step 3: Find the molar mass of CO.
The molar mass of carbon monoxide (CO) is calculated by adding the atomic masses of carbon (C) and oxygen (O):

- Atomic mass of C = 12 g/mol
- Atomic mass of O = 16 g/mol

Thus, the molar mass of CO is:

\[ \text{Molar mass of CO} = 12 + 16 = 28 \text{ g/mol} \]

### Step 4: Calculate the weight using the number of moles and molar mass.
We can find the weight (mass) of the substance using the formula:

\[ \text{Weight} = n \times \text{Molar mass} \]

Substituting the values we have:

\[ \text{Weight} = 0.0334 \text{ moles} \times 28 \text{ g/mol} \]

### Step 5: Perform the final calculation.
Now we calculate the weight:

\[ \text{Weight} = 0.934 \text{ grams} \]

### Final Answer:
The weight of \(2.01 \times 10^{22}\) molecules of CO is approximately **0.934 grams**.

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