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The ratio of mass percent of C and H of ...

The ratio of mass percent of C and H of an organic compound (`C_xH_yO_z`) is 6 : 1. If one molecule of the above compound (`C_xH_yO_z`) contains half as much oxygen as required to burn one molecule of compound `C_xH_y` completely to `CO_(2)` and `H_2O`. The empirical formula of compound `C_xH_yO_z` is:

A

`C_(2)H_(4)O`

B

`C_(3)H_(4)O_(2)`

C

`C_(2)H_(4)O_(3)`

D

`C_(3)H_(6)O_(3)`

Text Solution

Verified by Experts

The correct Answer is:
C
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