Home
Class 12
PHYSICS
In the figure shown the acceleration of ...

In the figure shown the acceleration of A is, `bara_(A)=(15hati+15hatj)m//s^(2).` If A is sliding on B then the acceleration of B is.

Text Solution

Verified by Experts

The correct Answer is:
`-5hatim//s^(2)`
Promotional Banner

Topper's Solved these Questions

  • NEWTON'S LAWS OF MOTION & FRICTION

    ALLEN|Exercise EXERCISE (O-1)|51 Videos
  • NEWTON'S LAWS OF MOTION & FRICTION

    ALLEN|Exercise EXERCISE (O-2)|31 Videos
  • NEWTON'S LAWS OF MOTION & FRICTION

    ALLEN|Exercise EXERCISE (S-1)|23 Videos
  • MOTION IN A PALNE

    ALLEN|Exercise SOLVED EXAMPLE|28 Videos
  • NEWTONS LAWS OF MOTION

    ALLEN|Exercise EXERCISE-III|28 Videos

Similar Questions

Explore conceptually related problems

In the figure shown acceleration of the block is

In the figure shown the accelerationof A is a_(A) = (15 hati + 15 hatj) . Then the acceleration of B is (A remain in contact with B)

In fig, the acceleration of A is vec(a)_(A)=15hat(i)+15hat(j) . Then the acceleration of B is (A remains in constact with B)

In the figure shown, the acceleration of block of mass m_(2) is 2m//s^(2) . The acceleration of m_(1) :

If acceleration of A is 2m//s^(2) to left and acceleration of B is 1m//s^(2) to left, then acceleration of C is-

The block C shown in the figure is ascending with an acceleration a=3m//s^(2) by means of some motor not shown here. Find the acceleration of the bodies A and B of masses 10 kg and 5kg respectively in m//s^(2) , assuming pulleys are massless and friction is absent everywhere.

In the pully system shown, if radii of the bigger and smaller pulley are 2m and 1m respectively and the acceleration of block A is 5 m//s^(2) in the downward direction, then the acceleration of block B will be

Block A is kept on block B as shown in figure. It is known that acceleration of block A is 2 m//s^(2) towards right and acceleration of block B is 3 m//s^(2) towards right under the effect of unknown forces. Direction of friction force acting on A by B (mu_(AB) = 0.3)

Assertion: A block A is just placed inside a smooth box B as shown in figure. Now the box is given an acceleration a = (2 hat(i) - 2 hat(j)) m//s ^(-2) . Under the acceleration block A cannot remain in the position shown. Reason: Block will require ma force for moving with acceleration a .

If acceleration of A is 2m//s^(2) which is smaller than acceleration of B then the value of frictional force applied by B on A is