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A man is standing at point (x=5m, y=0) ....

A man is standing at point `(x=5m, y=0)` . Then be walks along staight line to `(x=0 , y=5m)` . A second man walks from the same initial position along the x-axis to the arigin and then along the y-axis to `(x=0, y=5m)` . Mark the correct statement(s) :

A

Displacement vector of first man and second man are equal

B

Distance travelled by second man is greater.

C

Magnitude of displacement of second man is same that of first man but direction is different

D

Magnitude of displacement is `sqrt(50)m` for `2^(nd)` man.

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem step by step, we will analyze the movements of both men and determine the correct statements based on their displacements and distances traveled. ### Step 1: Identify the Positions - The first man starts at point \( P(5, 0) \) and walks to point \( Q(0, 5) \). - The second man also starts at point \( P(5, 0) \), walks to the origin \( O(0, 0) \), and then to point \( Q(0, 5) \). ### Step 2: Calculate the Displacement of Both Men - **Displacement of the First Man (A)**: - The displacement vector from \( P \) to \( Q \) can be calculated as: \[ \text{Displacement (A)} = Q - P = (0, 5) - (5, 0) = (-5, 5) \] - **Displacement of the Second Man (B)**: - The displacement vector from \( P \) to \( Q \) is the same: \[ \text{Displacement (B)} = Q - P = (0, 5) - (5, 0) = (-5, 5) \] ### Step 3: Compare the Displacements - Both men have the same displacement vector \( (-5, 5) \). Thus, the magnitude and direction of their displacements are equal. ### Step 4: Calculate the Distance Traveled by Both Men - **Distance Traveled by the First Man (A)**: - The distance traveled is simply the length of the straight line from \( P \) to \( Q \): \[ \text{Distance (A)} = \sqrt{(0 - 5)^2 + (5 - 0)^2} = \sqrt{25 + 25} = \sqrt{50} \text{ m} \] - **Distance Traveled by the Second Man (B)**: - The second man travels from \( P \) to \( O \) and then to \( Q \): \[ \text{Distance (B)} = OP + OQ = 5 \text{ m} + 5 \text{ m} = 10 \text{ m} \] ### Step 5: Analyze the Statements 1. **Statement A**: The displacement vector for the first man and second man are equal. - **True**: Both have the same displacement vector \( (-5, 5) \). 2. **Statement B**: The distance traveled by the second man is greater. - **True**: Distance traveled by man A is \( \sqrt{50} \) m, while man B travels \( 10 \) m. 3. **Statement C**: The magnitude of displacement of the second man is the same as that of the first man, but the direction is different. - **False**: Both the magnitude and direction of displacement are the same for both men. 4. **Statement D**: The magnitude of displacement is \( \sqrt{50} \) m for the second man. - **False**: The magnitude of displacement for both men is \( \sqrt{50} \) m, not just for the second man. ### Conclusion The correct statements are: - Statement A: True - Statement B: True - Statement C: False - Statement D: False ### Final Answer The correct options are A and B.
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