Propene on reaction with `ICl` produces mainly

Options

A. 1-chloro-2-iodopropene
B. 2-chloro-1-iodopropane
C. `(+-)-2-"chloro"-1-"iodopropane"`
D. `(+-)-1-"chloro"-2-"iodopropane"`

Answer

To solve the question "Propene on reaction with ICl produces mainly," we will follow these steps:

### Step 1: Identify the structure of propene
Propene is an alkene with the molecular formula C₃H₆. Its structure can be represented as:
\[ \text{CH}_3\text{CH}=\text{CH}_2 \]

### Step 2: Understand the reaction with ICl
When propene reacts with iodine monochloride (ICl), it undergoes an electrophilic addition reaction. In this reaction, the double bond in propene acts as a nucleophile and attacks the electrophilic iodine (I⁺) from ICl.

### Step 3: Mechanism of the reaction
1. The double bond in propene attacks the iodine, forming a cyclic ion intermediate.
2. The chlorine ion (Cl⁻) then attacks the more substituted carbon atom of the intermediate.

### Step 4: Determine the product
The product formed from the reaction of propene with ICl is:
- The iodine atom will attach to the terminal carbon (C-1), and the chlorine atom will attach to the second carbon (C-2).
- This results in the formation of 2-chloro-1-iodopropane.

### Step 5: Write the final product
The final product can be represented as:
\[ \text{CH}_3\text{CHCl}\text{CH}_2\text{I} \]
This compound is known as 2-chloro-1-iodopropane.

### Conclusion
Thus, the main product formed when propene reacts with ICl is **2-chloro-1-iodopropane**.

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