Which of the following compound on treatment with `LiAlH_(4)` will give a product that will give positive lodoform test?

Options

A. `(a)CH_(3)CH_(2)CHO`
B. (b)`CH_(3)CH_(2)CO_(2)CH_(3)`
C. (c)`CH_(3)CH_(2)OCH_(2)CH_(2)CH_(3)`
D. (d)`CH_(3)COCH_(3)`

Answer

To solve the question regarding which compound will give a positive iodoform test upon treatment with LiAlH4, we need to follow these steps:

### Step-by-Step Solution:

1. **Understand the Reactant - LiAlH4**:
- Lithium aluminium hydride (LiAlH4) is a strong reducing agent. It reduces aldehydes, ketones, esters, and other carbonyl compounds to their corresponding alcohols.

2. **Identify the Iodoform Test**:
- The iodoform test is used to identify the presence of methyl ketones (compounds of the form RCOCH3) or secondary alcohols that can be oxidized to methyl ketones.

3. **Analyze Each Compound**:
- **Compound A: CH3CH2CHO (an aldehyde)**:
- When reduced by LiAlH4, it forms CH3CH2CH2OH (a primary alcohol).
- Primary alcohols do not give a positive iodoform test.

- **Compound B: CH3CH2C(=O)OCH3 (an ester)**:
- Upon reduction, it breaks down to CH3CH2CH2OH (a primary alcohol) and CH3OH (methanol).
- Again, primary alcohols do not give a positive iodoform test.

- **Compound C: CH3CH2OCH2CH2CH3 (an ether)**:
- Ethers are generally resistant to reduction by LiAlH4 and do not yield any products that would give a positive iodoform test.

- **Compound D: CH3C(=O)CH3 (a ketone)**:
- When reduced, it forms CH3C(OH)CH3 (a secondary alcohol).
- Secondary alcohols can be oxidized to methyl ketones and thus will give a positive iodoform test.

4. **Conclusion**:
- Among the given compounds, only **Compound D (acetone)** will yield a product that gives a positive iodoform test after treatment with LiAlH4.

### Final Answer:
The compound that will give a product that will give a positive iodoform test upon treatment with LiAlH4 is **Compound D (acetone)**.

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