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The kinetic energy of a particle of mass...

The kinetic energy of a particle of mass m moving with speed v is given by `K= (1)/(2) mv^(2) `. If the kinetic energy of a particle moving along x-axis varies with x as `K(x)=9-x^(2)`, then the region in which particle lies is :

A

`ML^(5)T^(-2)`

B

`M^(0)L^(3)T^(0)`

C

`ML^(-1)T^(-2)`

D

`M^(0)L^(6)T^(0)`

Text Solution

Verified by Experts

The correct Answer is:
D
`[(ab)/(RT)]=[(PV^(2))/(PV)]=[V^(2)]=M^(0)L^(6)T^(0)`
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