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If tan theta=(1)/sqrt(5) and theta lies ...

If `tan theta=(1)/sqrt(5)` and `theta` lies in the first quadrant, the value of `cos theta` is :

A

Energy

B

Force

C

Specific heat

D

Latent heat

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The correct Answer is:
To find the value of \( \cos \theta \) given that \( \tan \theta = \frac{1}{\sqrt{5}} \) and \( \theta \) lies in the first quadrant, we can follow these steps: ### Step 1: Understand the relationship of tangent in a right triangle The tangent of an angle in a right triangle is defined as the ratio of the length of the opposite side (perpendicular) to the length of the adjacent side (base). Therefore, we can express this as: \[ \tan \theta = \frac{\text{opposite}}{\text{adjacent}} = \frac{1}{\sqrt{5}} \] ### Step 2: Assign values to the sides of the triangle For simplicity, let's assign the length of the opposite side (perpendicular) as \( 1 \) and the length of the adjacent side (base) as \( \sqrt{5} \). Thus, we have: - Opposite side = \( 1 \) - Adjacent side = \( \sqrt{5} \) ### Step 3: Use the Pythagorean theorem to find the hypotenuse According to the Pythagorean theorem, the hypotenuse \( h \) can be calculated as: \[ h = \sqrt{(\text{opposite})^2 + (\text{adjacent})^2} = \sqrt{1^2 + (\sqrt{5})^2} \] Calculating this gives: \[ h = \sqrt{1 + 5} = \sqrt{6} \] ### Step 4: Calculate \( \cos \theta \) The cosine of an angle is defined as the ratio of the length of the adjacent side to the length of the hypotenuse: \[ \cos \theta = \frac{\text{adjacent}}{\text{hypotenuse}} = \frac{\sqrt{5}}{\sqrt{6}} \] ### Final Answer Thus, the value of \( \cos \theta \) is: \[ \cos \theta = \frac{\sqrt{5}}{\sqrt{6}} \]

To find the value of \( \cos \theta \) given that \( \tan \theta = \frac{1}{\sqrt{5}} \) and \( \theta \) lies in the first quadrant, we can follow these steps: ### Step 1: Understand the relationship of tangent in a right triangle The tangent of an angle in a right triangle is defined as the ratio of the length of the opposite side (perpendicular) to the length of the adjacent side (base). Therefore, we can express this as: \[ \tan \theta = \frac{\text{opposite}}{\text{adjacent}} = \frac{1}{\sqrt{5}} \] ...
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