A particle straight line passes through orgin and a point whose abscissa is double of ordinate of the point. The equation of such straight line is :

Options

A. `2bhat(j)`
B. `a hat(j)`
C. `(a-2b)hat(i)`
D. None of these

Explanation

To solve the problem, we need to find the equation of a straight line that passes through the origin and a point where the abscissa (x-coordinate) is double the ordinate (y-coordinate).

### Step-by-Step Solution:

1. **Understanding the Coordinates**:
- Let the point be represented as (x, y).
- According to the problem, the abscissa (x) is double the ordinate (y). This can be expressed mathematically as:
\[ x = 2y \]

2. **Expressing y in terms of x**:
- From the equation \(x = 2y\), we can rearrange it to express y in terms of x:
\[ y = \frac{x}{2} \]

3. **Finding the Equation of the Line**:
- The equation \(y = \frac{x}{2}\) represents a straight line. This line passes through the origin (0, 0) because when \(x = 0\), \(y\) also equals 0.
- The slope of the line is \(\frac{1}{2}\), which indicates that for every 2 units moved in the x-direction, the line moves 1 unit in the y-direction.

4. **Final Equation**:
- Therefore, the equation of the straight line that passes through the origin and the point where the abscissa is double the ordinate is:
\[ y = \frac{x}{2} \]

### Summary:
The equation of the straight line is \(y = \frac{x}{2}\).