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1 cm on the main scale of a vernier call...

`1 cm` on the main scale of a vernier callipers is divided into 10 equal parts. If 10 divisions of vernier coincide with 8 small divisions of main scale, then the least count of vernier calliper is

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The correct Answer is:
`8`
`1/2 mv^(2)=(-Kqe)/(r)`
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1 cm on the main scale of a vernier callipers is divided into 10 equal parts. If 10 divisions of vernier coincide with 8 small divisions of main scale, then the least count of the calliper is.

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