A particle experiences a constant acceleration for 20 sec after starting from rest. If it travels distance `S_1` in the first 10 sec and a distance `S_2` in the next 10 sec, Then

Answer

B, C

Explanation

`:'` Horizontal component of velocity remains constant
`:. v sin theta=v cos theta` (from figure) `:. v'=v cot theta`

So from `v_(y)=u_(y)+a_(y)trarr -v' cos theta`
`=sintheta-g t-v(cos^(2)theta)/(sin theta)=v sintheta-g t :. t=v/g cosec theta`