The varation of velocity of a particle with time moving along a straight line is illustrated in the adjoining figure. The distance travelled by the particle in 4 s is

Options

A. `10 m//s`
B. `12 m//s`
C. `15 m//s`
D. `20 m//s`

Answer

A

Explanation

After `t=1` sec, the speed increases with
`a=g sin 37^(@)=6 m//s^(2)`
`:. V_(y)=g sin 37^(@)xx1=6 m//s`
`:.` speed `=sqrt(8^(2)+6^(2))=10 m//s`