A body starting from rest moves along a straight line with a constant acceleration. The variation of speed (v) with distance (s) is represented by the graph

Options

A. `7 m//s^(2)` downwards
B. `2 m//s^(2)` downwards
C. `10 m//s^(2)` downwards
D. `8 m//s^(2)` downwards

Answer

C

Explanation

`a_(1)+a_(2)=1`
`a_(1)-a_(2)=7`
`a_(3)-a_(1)=2`
`rArr a_(1)=4`,
`a_(2)=-3`,
`a_(3)=6`
Acceleration of D`=a_(1)+a_(3)`
`=4+6=10 ms^(-2)` downwords