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Let r(1)(t)=3t hat(i)+4t^(2)hat(j) and...

Let `r_(1)(t)=3t hat(i)+4t^(2)hat(j)`
and `r_(2)(t)=4t^(2) hat(i)+3t^()hat(j)`
represent the positions of particles 1 and 2, respectively, as function of time t, `r_(1)(t)` and `r_(2)(t)` are in meter and t in second. The relative speed of the two particle at the instant t = 1s, will be

A

`sqrt(3/10)s`

B

`sqrt(10/3)s`

C

`1s`

D

`2s`

Text Solution

Verified by Experts

The correct Answer is:
A
Time of fight `=(2u sin theta)/g=(2xxsqrt(10)xxsqrt(3)/2)/10=sqrt(3)/10`
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