A particle id dropped from trst from a large height. Assume `g` to be constant throughout the motion. The time taken by it to fall throughout the successive distances of `1 m` each will be .

Options

A. all equal, being equal to `sqrt((2)/(g))` second.
B. in the ratio of the square roots of the integers 1: `sqrt(2):sqrt(3)`
C. in the ratio of the difference in the square roots of the integers,` i.e., sqrt(1),,(sqrt(2)-sqrt(q)),(sqrt(3)-sqrt(2)),(sqrt(4)-sqrt(3))`......
D. in the ratio of the reciprocals of the square roots of the intergers, ie., `(1)/sqrt(1),(1)/sqrt(2),(1)/sqrt(3)`....

Answer

C

Explanation

`because h=(1)/(2)"gt"^(2) thereforet=sqrt((2h)/(g))`