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The range of a projectile when fired at ...

The range of a projectile when fired at `75^(@)` with the horizontal is 0.5 km what will be its range when fired at `45^(@)` with same speed

A

0.5 km.

B

1.0 km.

C

1.5 km.

D

2.0 km.

Text Solution

Verified by Experts

The correct Answer is:
B
`0.5=u^(2)sin(2xx75^(@))/(g)rArr 0.5(u^(2))/(g)xx(1)/(2)`
`(u^(2))/(g)=1 rArr R=(u^(2)sin(2xx45^(@)))/(g)=(u^(2))/(g)=1km`
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