A projectile is thrown to have thte maximum possible horizontal range of 400 m. Taking the point of projecting as the origin, the co-ordinate of the point where the velocity of the projectile is minimum are

Options

A. -400100
B. -200100
C. -400200
D. -200200

Answer

B

Explanation

for maximum range `theta=45^(@)`
`because tan theta =(4H)/(R)`
`H=(R)/(4) tan 45^(@)=(400)/(4)=100`
`therefore` required coordinates are `((R)/(2),H)=(200,100)`