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A javelin thrown into air at an angle wi...

A javelin thrown into air at an angle with the horizontal has a range of 200 m. If the time of flight is 5 second, then the horizontal component of velocity of the projectile at the highest point of the trajectory is

A

`25m//s`

B

`40m//s`

C

`31.25 m//s`

D

`12.5m//s`

Text Solution

Verified by Experts

The correct Answer is:
B
`R=u_(x)tTrArr u_(x)=(R)/(T)=(200)/(5)=40m//s`
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