When a particle is thrown horizontally with velocity u from the top of a tower, the resultant velocity of the projectile at any time t during its flight is given by

Options

A. gt
B. `(1)/(2)"gt"^(2)`
C. `sqrt(u^(2)+g^(2)t^(2))`
D. `sqrt(u^(2)-g^(2)t^(2))`

Answer

C

Explanation

`v_(y)=0+gt`
`v=sqrt(v_(x)^(2)+v_(y)^(2))=sqrt(u^(2)+g^(2)t^(2))`