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Statement-I : A projectile is thrown wit...

Statement-I : A projectile is thrown with an initial velocity of `(ahat(i)+bhat(j)) m//s`. If range of projectile is maximum then `a=b`.
Statement-II : In projectile motion, angle of projection is equal to `45^(@)` for maximum range condition.

A

If both assertion `&` Reason are True `&` the Reason is a corrrect explanation of the Asserion.

B

If both Assertion `&` Reason are True but Reason is not correct explanation of the Assertion.

C

If Assertion is Trie but the Reason is False.

D

If both Assertion `&` Reason are false

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to analyze the statements given regarding projectile motion. ### Step 1: Understanding the Components of Initial Velocity The initial velocity of the projectile is given as \( \vec{u} = a \hat{i} + b \hat{j} \) m/s. Here, \( a \) is the horizontal component (along the x-axis) and \( b \) is the vertical component (along the y-axis). **Hint:** Recall that the horizontal and vertical components of velocity are crucial in determining the trajectory of the projectile. ### Step 2: Expression for Range of Projectile The range \( R \) of a projectile launched at an angle \( \theta \) with an initial velocity \( u \) is given by the formula: \[ R = \frac{u^2 \sin 2\theta}{g} \] where \( g \) is the acceleration due to gravity. **Hint:** Remember that the maximum range occurs when \( \sin 2\theta = 1 \). ### Step 3: Condition for Maximum Range The value of \( \sin 2\theta \) is maximum (equal to 1) when \( 2\theta = 90^\circ \), which implies \( \theta = 45^\circ \). **Hint:** Think about how the angle of projection affects the range of the projectile. ### Step 4: Components at 45 Degrees When the angle of projection \( \theta = 45^\circ \), the components of the initial velocity can be expressed as: \[ u_x = u \cos 45^\circ = \frac{u}{\sqrt{2}}, \quad u_y = u \sin 45^\circ = \frac{u}{\sqrt{2}} \] This means that the horizontal and vertical components of the initial velocity are equal. **Hint:** Consider how trigonometric functions behave at \( 45^\circ \). ### Step 5: Relating Components to Statements From the above, if \( a = u_x \) and \( b = u_y \) at \( 45^\circ \), we find that: \[ a = b \] This confirms Statement I, which states that if the range of the projectile is maximum, then \( a = b \). **Hint:** Reflect on how the equality of components leads to the conclusion about the angle of projection. ### Step 6: Conclusion about Statements - **Statement I** is true: For maximum range, \( a \) must equal \( b \). - **Statement II** is also true: The angle of projection for maximum range is indeed \( 45^\circ \). Thus, both statements are true, and Statement II provides the correct explanation for Statement I. **Final Conclusion:** Both Statement I and Statement II are true, and Statement II is the correct explanation for Statement I.
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