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A current of 3 A flows through the 2 Ome...

A current of 3 A flows through the `2 Omega ` resistor shown in the circuit below. The power dissipated in the `5 Omega` resistor is

A

`(mv^(2))/(2 (L - nr))`

B

`(mv^(2))/(L - nr)`

C

zero

D

`(mv^(2))/(L - 2 nr)`

Text Solution

Verified by Experts

The correct Answer is:
D

Change In momentum in each collision with rigid support `DeltaP = 2mv`
time gap between two successive collision with same support `Deltat = (2L - 4nr)/(v)`
`F_("ave") = (DeltaP)/(Deltat)`
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