A particle with velocity `vec(v)_(0)=-2hat(i)+4hat(j)` (in meters per second) at `t = 0` undergoes a constant acceleration a of magnitude `a =3m//s^(2)` at an angle `theta=127^(@)` from the positive direction of the x axis. What is the particle's velocity `vec(a)` at `t=5` sec, in unit vector notation ?

Explanation

To solve the problem step by step, we will find the particle's velocity at \( t = 5 \) seconds given its initial velocity and constant acceleration.

### Step 1: Identify the initial velocity
The initial velocity of the particle is given as:
\[ \vec{v}_0 = -2 \hat{i} + 4 \hat{j} \, \text{m/s} \]
This means:
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