Prithvi missile is fired to destroy an enemy military base situated on same horizontal level, situated 99 km away. The missile rises vertically for 1 km & then for remainder of flight, it followes parbolic path like a free body under earth's gravity, at an angle of `45^(@)`. Calculate its velocity at beginning of parabolic path. `(g=10 ms^(-2))`

Explanation

To solve the problem of calculating the velocity of the Prithvi missile at the beginning of its parabolic path, we can break it down into several steps:

### Step 1: Understand the problem
The missile rises vertically for 1 km and then follows a parabolic path at an angle of 45 degrees to cover a horizontal distance of 99 km. We need to find the initial velocity of the missile at the beginning of the parabolic path.

### Step 2: Set up the coordinate system
Let's denote:
- The vertical displacement (rise) as \( s_y = 1 \, \text{km} = 1000 \, \text{m} \) (upward).
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