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A man when standstill observes the rain ...

A man when standstill observes the rain falling vertically and when he walks at `4 km//h` he has to hold his umberella at an angle `53^(@)` from the vertical. Find velocity of the raindrops.

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To solve the problem, we need to analyze the situation using vector components and the concept of relative velocity. Here’s a step-by-step solution: ### Step 1: Understand the Situation When the man is standing still, he observes the rain falling vertically. This means that the velocity of the raindrops (V_rain) is directed straight downwards. ### Step 2: Analyze the Man's Movement When the man walks at a speed of 4 km/h, he has to hold his umbrella at an angle of 53 degrees from the vertical to keep himself dry. This indicates that the rain is not falling straight down relative to him; instead, it has a horizontal component due to his movement. ...
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By the term velocity of rain, we mean velocity with which raindrops fall relative to the ground. In absence of wind, raindrops fall vertically and in presence of wind raindrops fall obliqucly. Moreover raindrops acquire a constant terminal velocity due air resistance very quickly as they fall toward the carth. A moving man relative to himself observes an altered velocity of raindrops. Which is known as velocity of rain relative to the man. It is given by the following equation. vec(v)_(rm)=vec(v)_(r)-vec(v)_(m) A standstill man relative to himself observes rain falling with velocity, which is equal to velocity of the raindrops relative to the ground. To protect himself a man should his umbrella against velocity of raindrops relative to himself as shown in the following figure. A man walks in rain at 72 cm/m due east and observes the rain falling vertically. When he stops, rain appears to strike his back at 37^(@) from the vertical. Find velocity of raindrops relative to the ground.

A person walking ,on a horizontal road at 2 km/h finds that the rain is falling vertically . Now the person increasses his speed to 4 km/h and find that rain makes an angle 45^(@) with the vertical . Find the velocity of rain with respect to the road.

A man starts running along a straight road with uniform velocity observes that the rain is falling vertically downward. If he doubles his speed, he finds that the rain is coming at an angle theta to the vertical. The velocity of rain with respect to the ground is :

A man starts running along a straight road with uniform velocity observes that the rain is falling vertically downward. If he doubles his speed, he finds that the rain is coming at an angle theta to the vertical. The velocity of rain with respect to the ground is :

To a man walking at the rate of 3 km//h the rain appear to fall vertically downwards. When he increases his speed 6 km//h it appears to meet him at an angle of 45^@ with vertically. Find the speed of rain.

A man walking with a speed of 3 km/h finds the rain drops falling vertically downwards. When the man increases his speed to 6km/h he find that the rain drops are falling making an angle of 30^(@) with the vertical . Find the speed of the rain drops ( in km/h)

A stationary man observes that the rain is falling vertically downwards. When he starts running a velocity of 12 kmh^(-1) , he observes that the rain is falling at an angle 60^(@) with the vertical. The actual velocity of rain is

A man running at a speed of 5 km/h finds that the rain is falling vertically. When the stops running, the finds that the rain is falling at an angle of 60^(@) with the horizontal. The velocity of rain with respect to running man is

By the term velocity of rain, we mean velocity with which raindrops fall relative to the ground. In absence of wind, raindrops fall vertically and in presence of wind raindrops fall obliqucly. Moreover raindrops acquire a constant terminal velocity due air resistance very quickly as they fall toward the carth. A moving man relative to himself observes an altered velocity of raindrops. Which is known as velocity of rain relative to the man. It is given by the following equation. vec(v)_(rm)=vec(v)_(r)-vec(v)_(m) A standstill man relative to himself observes rain falling with velocity, which is equal to velocity of the raindrops relative to the ground. To protect himself a man should his umbrella against velocity of raindrops relative to himself as shown in the following figure. When you are standstill in rain, you have to hold umbrella vertically to protect yourself. (a) When you walk with velocity 90 cm/s, you have to hold your umbrella at 53^(@) above the horizontal. What is velocity of the raindrops relative to the ground and relative to you ? (b) If you walk with speed 160 cm/s, how should you hold your umbrella ?

To a man walking at the rate of 4 km/h the rain appears to fall vertically. When he increases his speed 8 km/h it appears to meet him at an angle of 45 with vertical. Find the angle made by the velocity of rain with the vertical and its value.

ALLEN-KINEMATICS-2D-Exercise (O-2)
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  4. The position vector of a particle is deternined by the expression vecr...

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  9. A particle is projected an angle of 45^(@) from 8m before the foot of ...

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  14. In the time taken by the projectile to reach from A to B is t. Then th...

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  15. A particle is projected from a point P(2,0,0) m with a velocity 10 m//...

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  16. A body A is thrown vertically upwards with such a velocity that it rea...

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  17. An object moves to the East across a frictionless surface with constan...

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  18. A particle is thrown from a stationary platform with velocity v at an ...

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  19. On a particular day rain drops are falling vertically at a speed of 5 ...

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  20. A 2m wide truck is moving with a uniform speed v(0)=8m//s along a stra...

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