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Shown that for a projectile the angle be...

Shown that for a projectile the angle between the velocity and the x-axis as a function of time is given by
`theta(t)=tan^(-1)((v_(oy)-gt)/(v_(ax)))`
(b) Show that the projection angle `theta_(0)` for a projectile lauched from the origin is given by
`theta_(0)=(tan^(-1)(4h_(m))/(R))`
Where the symbols have their usual meaning.

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