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A boatman moves his boat with a velocity...

A boatman moves his boat with a velocity 'v' (relative to water) in river and finds to his surprise that velocity of river 'u' (with respect to ground) is more than 'v'. He has to reach a point directly opposite to the starting point on another bank by travelling minimum possible distance. Then

A

he must steer the boat (with velocity v) at certain angle with river flow so that he can reach the opposite point on other bank directly.

B

his velocity 'v' must be towards directly opposite point, So, that he can travel rest of distance by walking on other bank to reach the directly opposite point.

C

boatman should maintain velocity v of boat at certain angle greater than `90^(@)` with direction of river flow to minimize drifting and then walk rest of distance on other bank.

D

boat velocity 'v' should be at an angle less than `90^(@)` with direction of river flow to minimize the drift and then walk to the point.

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The correct Answer is:
To solve the problem, we need to analyze the motion of the boatman in the river. The goal is to reach a point directly opposite the starting point on the other bank while minimizing the distance traveled. ### Step-by-Step Solution: 1. **Understanding the Scenario**: - Let the velocity of the boat relative to the water be \( v \). - Let the velocity of the river (current) relative to the ground be \( u \). - Given that \( u > v \), the river flows faster than the boat can move. 2. **Setting Up the Coordinate System**: - Assume the river flows horizontally from left to right. - The boatman starts at point \( O \) on the left bank and wants to reach point \( A \) directly opposite on the right bank. 3. **Analyzing the Boat's Motion**: - The boat must be directed at an angle \( \theta \) with respect to the river flow to counteract the current and reach point \( A \). - The boat's velocity can be broken down into two components: - A component against the current (upstream) to counteract the river's velocity. - A vertical component to cross the river. 4. **Using Velocity Components**: - The upstream component of the boat's velocity can be expressed as \( v \cos(\theta) \). - The vertical component (across the river) is \( v \sin(\theta) \). 5. **Condition for Reaching Point A**: - To reach point \( A \), the upstream component must equal the river's velocity: \[ v \cos(\theta) = u \] - This means \( \theta \) must be such that the boat's upstream motion can counter the river's flow. 6. **Finding the Angle**: - Rearranging the equation gives: \[ \cos(\theta) = \frac{u}{v} \] - Since \( u > v \), \( \cos(\theta) \) will be negative, indicating that \( \theta \) must be greater than 90 degrees. 7. **Conclusion**: - The boatman should steer the boat at an angle greater than 90 degrees with respect to the direction of the river flow to reach the opposite bank directly. ### Final Answer: The correct option is that the boatman should maintain a velocity \( v \) of the boat at an angle greater than 90 degrees with the direction of river flow. ---
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