A cubical box dimension L = 5//4 m start...

A cubical box dimension `L = 5//4` m starts moving with an acceleration `veca = 0.5 ms^(-2) hati` form the state of rest. At the same time, a stone is thrown form the origin with velocity `vecV = v_1hati + v_2hatj - v_3hatk` with respect to earth. Acceleration due to gravity `vecg = 10ms^(-2)(-hatj)`. The stone just touches the roof of box and finally falls at the diagonally opposite point. then:

`v_(1)=3/2`

`v_(2)=5`

`v_(3)=5/4`

`v_(3)=5/2`

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