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Let X = (.^(10)C(1))^(2) + 2(.^(10)C(2))...

Let `X = (.^(10)C_(1))^(2) + 2(.^(10)C_(2))^(2) + 3(.^(10)C_(3))^(2) + "……" + 10(.^(10)C_(10))^(2)`, where `.^(10)C_(r ), r in {1,2,"….",10}` denotes binomial coefficients then the value of `(1)/(1430) X` is `"_____"`.

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