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A force is inclined at an angle of 60^(@...

A force is inclined at an angle of `60^(@)` from the horizontal. If the horizontal component of the force is 40N. Calculate the vertical component.

Text Solution

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` because A_x= A cos theta " "therefore 40 = A cos 60^(@) = (A)/(2) rArr A = 80 N `
Now `" "A_y= A sin 60 ^(@) = (Asqrt3)/(2) = (80sqrt3)/(2) = 40sqrt3N `
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