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A bullet loses ((1)/(n)) ^(th ) of its v...

A bullet loses `((1)/(n)) ^(th )` of its velocity passing through one plank. The number of such planks that are required to stop the bullet can be

Text Solution

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By using `v^(2) =u^(2) + 2as`
We have `(u- (u)/(n))^(2) =u^(2) + 2(-a)s`
`rArr ((2)/(n) - (1)/(n^(2)))u^(2) = 2as`
Let no. of placks required be N
Then,
` 0^(2) =u^(2) + 2(-a)Ns`
Therefore , `((2)/(n) - (1)/(n^(2)))u^(2) = (u^(2))/(N)`
`rArr N = (n^(2))/(2n-1)`
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