If the number of bivalents are 8 in metaphase - I, what shall be the number of chromosomes in daughter cells after meiosis -I and meiosis -II respectively:-

Options

A. 8 and 4
B. 4 and 4
C. 8 and 8
D. 16 and 8

Answer

To solve the question regarding the number of chromosomes in daughter cells after meiosis I and meiosis II, given that there are 8 bivalents in metaphase I, we can follow these steps:

### Step-by-Step Solution:

1. **Understanding Bivalents**:
- A bivalent consists of two homologous chromosomes. Therefore, if there are 8 bivalents present during metaphase I, we can calculate the total number of chromosomes.
- Calculation:
\[ \text{Total Chromosomes} = \text{Number of Bivalents} \times 2 = 8 \times 2 = 16 \]

2. **Meiosis I**:
- Meiosis I is known as the reductional division. This means that the number of chromosomes is halved.
- Since we started with 16 chromosomes, after meiosis I, the number of chromosomes will be:
- Calculation:
\[ \text{Chromosomes after Meiosis I} = \frac{16}{2} = 8 \]

3. **Meiosis II**:
- Meiosis II is similar to mitosis and is known as the equational division. The number of chromosomes remains the same as that in the daughter cells produced after meiosis I.
- Therefore, after meiosis II, the number of chromosomes will still be:
- Calculation:
\[ \text{Chromosomes after Meiosis II} = 8 \]

4. **Final Answer**:
- Thus, the number of chromosomes in daughter cells after meiosis I is 8, and after meiosis II is also 8.

### Summary:
- The number of chromosomes in daughter cells after meiosis I: **8**
- The number of chromosomes in daughter cells after meiosis II: **8**