If n=16 in plant cell, then how many bivalents in metaphase-I of meiosis are possible ?

Options

A. 32 Bivalents
B. 16 Telravalents
C. 16 Bivalents
D. 32 Bivalents

Answer

To determine the number of bivalents present in metaphase I of meiosis when the haploid number (n) is 16, we can follow these steps:

### Step-by-Step Solution:

1. **Understand the Concept of Bivalents**:
- Bivalents are structures formed during meiosis when homologous chromosomes pair up. Each bivalent consists of two homologous chromosomes.

2. **Identify the Haploid Number**:
- The question states that n = 16. This means that in a haploid cell, there are 16 chromosomes.

3. **Determine the Diploid Number**:
- In a diploid cell, the number of chromosomes is double that of the haploid number. Therefore, the diploid number (2n) will be:
\[ 2n = 2 \times 16 = 32 \]
- This means there are 32 chromosomes present in a diploid cell during metaphase I.

4. **Formation of Bivalents**:
- During prophase I of meiosis, homologous chromosomes pair up to form bivalents. Since each bivalent consists of a pair of homologous chromosomes, the number of bivalents formed will be half the total number of chromosomes in the diploid state.

5. **Calculate the Number of Bivalents**:
- Since there are 32 chromosomes in total during metaphase I, the number of bivalents will be:
\[ \text{Number of bivalents} = \frac{32}{2} = 16 \]

6. **Conclusion**:
- Therefore, the number of bivalents present in metaphase I of meiosis is **16**.

### Final Answer:
The number of bivalents in metaphase I of meiosis is **16**.

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