The conjugate base of `(CH_(3))_(2)overset(+)(NH_(2))` is :-

Options

A. `CH_(3)NH_(2)`
B. `(CH_(3))_(2)N^(+)`
C. `(CH_(3))_(2)N`
D. `(CH_(3))_(2)NH`

Answer

To find the conjugate base of the compound \((CH_3)_2NH_2^+\), we need to follow these steps:

### Step 1: Understand the Concept of Conjugate Bases
A conjugate base is formed when an acid donates a proton (H⁺). In this case, \((CH_3)_2NH_2^+\) is acting as a proton donor.

**Hint:** Remember that acids donate protons to form their conjugate bases.

### Step 2: Identify the Structure of the Given Compound
The given compound is \((CH_3)_2NH_2^+\). This is a positively charged ammonium ion where two methyl groups \((CH_3)\) are attached to the nitrogen atom, and there are two hydrogen atoms.

**Hint:** Visualize the structure to understand how the proton donation will occur.

### Step 3: Remove a Proton from the Compound
To find the conjugate base, we need to remove one proton (H⁺) from \((CH_3)_2NH_2^+\). When we remove one proton from the ammonium ion, we are left with \((CH_3)_2NH\).

**Hint:** Focus on the nitrogen atom, as it is where the proton will be removed.

### Step 4: Write the Conjugate Base
After removing one proton from \((CH_3)_2NH_2^+\), we obtain the conjugate base, which is \((CH_3)_2NH\).

**Hint:** Ensure that the charge is balanced after the proton removal.

### Conclusion
The conjugate base of \((CH_3)_2NH_2^+\) is \((CH_3)_2NH\).

### Final Answer
The conjugate base of \((CH_3)_2NH_2^+\) is \((CH_3)_2NH\).

---