Heavy water reacts respectively with `CO_(2),SO_(3), P_(2)O_(5) and N_(2)O_(5)` to give the compounds :

Options

A. `D_(2)CO_(3),D_(2)SO_(4),D_(3)PO_(2),DNO_(2)`
B. `D_(2)CO_(3),D_(2)SO_(4),D_(3)PO_(4),DNO_(2)`
C. `D_(2)CO_(3),D_(2)SO_(3),D_(3)PO_(4),DNO_(2)`
D. `D_(2)CO_(3),D_(2)SO_(4),D_(3)PO_(4),DNO_(3)`

Answer

To solve the question regarding the reactions of heavy water (D2O) with CO2, SO3, P2O5, and N2O5, we will follow these steps:

### Step 1: Identify Heavy Water
Heavy water is chemically represented as D2O, where D is deuterium, an isotope of hydrogen.

### Step 2: Reaction of D2O with CO2
When heavy water (D2O) reacts with carbon dioxide (CO2), it produces deuterium carbonate (D2CO3).
- **Reaction:**
D2O + CO2 → D2CO3

### Step 3: Reaction of D2O with SO3
When heavy water reacts with sulfur trioxide (SO3), it produces deuterium sulfate (D2SO4).
- **Reaction:**
D2O + SO3 → D2SO4

### Step 4: Reaction of D2O with P2O5
When heavy water reacts with phosphorus pentoxide (P2O5), it produces deuterium phosphate (D3PO4).
- **Reaction:**
D2O + P2O5 → D3PO4

### Step 5: Reaction of D2O with N2O5
When heavy water reacts with dinitrogen pentoxide (N2O5), it produces deuterium nitrate (DNO3).
- **Reaction:**
D2O + N2O5 → DNO3

### Final Summary of Products
The respective products formed from the reactions of heavy water with the given compounds are:
1. D2CO3 (from CO2)
2. D2SO4 (from SO3)
3. D3PO4 (from P2O5)
4. DNO3 (from N2O5)