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In the balanced equation - [Zn+H^(+)+N...

In the balanced equation -
`[Zn+H^(+)+NO_(3)^(-)rarr NH_(4)^(+) +Zn^(+2)+H_(2)O]`
coefficient of `NH_(4)^(+)` is :-

A

4

B

3

C

2

D

1

Text Solution

AI Generated Solution

The correct Answer is:
To find the coefficient of \( NH_4^+ \) in the balanced equation: \[ Zn + H^+ + NO_3^- \rightarrow NH_4^+ + Zn^{2+} + H_2O \] we need to balance the equation step by step. ### Step 1: Write down the unbalanced equation The unbalanced equation is: \[ Zn + H^+ + NO_3^- \rightarrow NH_4^+ + Zn^{2+} + H_2O \] ### Step 2: Balance the zinc (Zn) atoms On the left side, there is 1 zinc atom from \( Zn \) and on the right side, there is also 1 zinc atom from \( Zn^{2+} \). Thus, zinc is balanced. ### Step 3: Balance the nitrogen (N) atoms On the left side, there is 1 nitrogen atom from \( NO_3^- \) and on the right side, there is 1 nitrogen atom from \( NH_4^+ \). Thus, nitrogen is balanced. ### Step 4: Balance the hydrogen (H) atoms On the left side, we have 1 \( H^+ \) ion, and on the right side, we have 4 \( H \) from \( NH_4^+ \) and 2 \( H \) from \( H_2O \) (totaling 6 H). To balance the hydrogen atoms, we need to adjust the number of \( H^+ \) ions on the left side. To balance, we will multiply \( H^+ \) by 6: \[ 6H^+ \] ### Step 5: Balance the oxygen (O) atoms Now, we have 3 oxygen atoms from \( NO_3^- \) on the left side and 1 oxygen atom from \( H_2O \) on the right side. To balance the oxygen atoms, we will multiply \( H_2O \) by 3: \[ 3H_2O \] Now, we have: - Left side: 3 oxygen from \( NO_3^- \) - Right side: 3 oxygen from \( 3H_2O \) ### Step 6: Write the balanced equation Now, the balanced equation is: \[ Zn + 6H^+ + NO_3^- \rightarrow NH_4^+ + Zn^{2+} + 3H_2O \] ### Step 7: Identify the coefficient of \( NH_4^+ \) In the balanced equation, the coefficient of \( NH_4^+ \) is 1. ### Final Answer The coefficient of \( NH_4^+ \) is **1**. ---
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ALLEN-REDOX REACTIONS-EXERICSE - 2
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