Match List - I (compound) with list - II (Oxidation state of N) and select the correct answer using the codes given below the list :-
`{:(" List - I"," List - II"),((A)KNO_(3),(a)-1//3),((B)HNO_(2),(b)-3),((C)NH_(4)Cl,(c)0),((D)NaN_(3),(d)+3),(,(e) +5):}`

Options

A. `{:(A,B,C,D),(e,d,b,a):}`
B. `{:(A,B,C,D),(e,b,d,a):}`
C. `{:(A,B,C,D),(d,e,a,c):}`
D. `{:(A,B,C,D),(b,c,d,e):}`

Answer

To solve the problem of matching compounds with their respective oxidation states of nitrogen, we will analyze each compound step by step.

### Step 1: Determine the oxidation state of nitrogen in KNO₃

1. **Identify the oxidation states of other elements**:
- Potassium (K) has an oxidation state of +1.
- Oxygen (O) has an oxidation state of -2.

2. **Set up the equation**:
- The formula for KNO₃ is K + N + 3O = 0.
- This translates to:
\[ +1 + X + 3(-2) = 0 \]
- Simplifying gives:
\[ +1 + X - 6 = 0 \implies X - 5 = 0 \implies X = +5 \]

3. **Conclusion**: The oxidation state of nitrogen in KNO₃ is **+5**.

### Step 2: Determine the oxidation state of nitrogen in HNO₂

1. **Identify the oxidation states of other elements**:
- Hydrogen (H) has an oxidation state of +1.
- Oxygen (O) has an oxidation state of -2.

2. **Set up the equation**:
- The formula for HNO₂ is H + N + 2O = 0.
- This translates to:
\[ +1 + X + 2(-2) = 0 \]
- Simplifying gives:
\[ +1 + X - 4 = 0 \implies X - 3 = 0 \implies X = +3 \]

3. **Conclusion**: The oxidation state of nitrogen in HNO₂ is **+3**.

### Step 3: Determine the oxidation state of nitrogen in NH₄Cl

1. **Identify the oxidation states of other elements**:
- Hydrogen (H) has an oxidation state of +1.
- Chlorine (Cl) has an oxidation state of -1.

2. **Set up the equation**:
- The formula for NH₄Cl is N + 4H + Cl = 0.
- This translates to:
\[ X + 4(+1) + (-1) = 0 \]
- Simplifying gives:
\[ X + 4 - 1 = 0 \implies X + 3 = 0 \implies X = -3 \]

3. **Conclusion**: The oxidation state of nitrogen in NH₄Cl is **-3**.

### Step 4: Determine the oxidation state of nitrogen in NaN₃

1. **Identify the oxidation states of other elements**:
- Sodium (Na) has an oxidation state of +1.

2. **Set up the equation**:
- The formula for NaN₃ is Na + 3N = 0.
- This translates to:
\[ +1 + 3X = 0 \]
- Simplifying gives:
\[ 3X = -1 \implies X = -\frac{1}{3} \]

3. **Conclusion**: The oxidation state of nitrogen in NaN₃ is **-\frac{1}{3}**.

### Final Matching of Compounds with Oxidation States

- KNO₃ → +5
- HNO₂ → +3
- NH₄Cl → -3
- NaN₃ → -\frac{1}{3}

### Summary of Matches
- A (KNO₃) → (e) +5
- B (HNO₂) → (d) +3
- C (NH₄Cl) → (b) -3
- D (NaN₃) → (a) -\frac{1}{3}

### Correct Answer Code
The correct answer code is **1**.

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