Which of the following compounds are arranged in increasing oxidation number of S :-

Options

A. `H_(2)SO_(3),H_(2)S,H_(2)SO_(4),H_(2)S_(2)O_(3)`
B. `H_(2)S_(2)O_(3),H_(2)SO_(3),H_(2)S,H_(2)SO_(4)`
C. `H_(2)S,H_(2)SO_(3),H_(2)SO_(4),H_(2)S_(2)O_(3)`
D. `H_(2)S,H_(2)S_(2)O_(3),H_(2)SO_(3),H_(2)SO_(4)`

Answer

To determine the increasing oxidation number of sulfur (S) in the given compounds, we will calculate the oxidation state of sulfur in each compound step by step.

### Step 1: Identify the compounds
The compounds we need to analyze are:
1. H₂S
2. H₂SO₃
3. H₂S₂O₃
4. H₂SO₄

### Step 2: Calculate the oxidation state of sulfur in each compound

#### For H₂S:
- Hydrogen (H) has an oxidation state of +1.
- Let the oxidation state of sulfur (S) be \( x \).
- The equation for the compound is:
\[ 2(+1) + x = 0 \]
\[ 2 + x = 0 \implies x = -2 \]
- **Oxidation state of S in H₂S = -2**

#### For H₂SO₃:
- Hydrogen (H) has an oxidation state of +1.
- Oxygen (O) has an oxidation state of -2.
- Let the oxidation state of sulfur (S) be \( x \).
- The equation for the compound is:
\[ 2(+1) + x + 3(-2) = 0 \]
\[ 2 + x - 6 = 0 \implies x - 4 = 0 \implies x = +4 \]
- **Oxidation state of S in H₂SO₃ = +4**

#### For H₂S₂O₃:
- This compound can be represented as H₂O + S=O + S + O + H₂O.
- The structure indicates that there are two sulfur atoms.
- Let the oxidation state of sulfur be \( x \) for one sulfur atom and \( y \) for the other.
- The equation for the compound is:
\[ 2(+1) + x + y + 3(-2) = 0 \]
- Assuming both sulfur atoms have the same oxidation state for simplicity:
\[ 2 + 2x - 6 = 0 \implies 2x - 4 = 0 \implies x = +2 \]
- **Oxidation state of S in H₂S₂O₃ = +2** (average oxidation state)

#### For H₂SO₄:
- Hydrogen (H) has an oxidation state of +1.
- Oxygen (O) has an oxidation state of -2.
- Let the oxidation state of sulfur (S) be \( x \).
- The equation for the compound is:
\[ 2(+1) + x + 4(-2) = 0 \]
\[ 2 + x - 8 = 0 \implies x - 6 = 0 \implies x = +6 \]
- **Oxidation state of S in H₂SO₄ = +6**

### Step 3: Arrange the oxidation states in increasing order
Now that we have calculated the oxidation states of sulfur in each compound, we can arrange them in increasing order:
1. H₂S: -2
2. H₂S₂O₃: +2
3. H₂SO₃: +4
4. H₂SO₄: +6

### Final Arrangement
The increasing order of oxidation numbers of sulfur in the compounds is:
- H₂S (-2) < H₂S₂O₃ (+2) < H₂SO₃ (+4) < H₂SO₄ (+6)

### Conclusion
The correct arrangement in increasing oxidation number of sulfur is:
**H₂S < H₂S₂O₃ < H₂SO₃ < H₂SO₄**